Solution
Save static equilibrium equations


Section K
Interval I \(x\in (0,2) \)
\begin{aligned} &Q_{k}=V_{A}-1=-0.2 x \\ &Q_{k}(0)=0 \quad Q_{k}(2)=-0.4 \end{aligned} \begin{aligned} &M_{k}=V_{A} \cdot 2-1(2-x)=2-0.4 x-2+x=0.6 x \\ &M_{k}(0)=0 \quad M_{k}(2)=1.2 \end{aligned} \begin{aligned} &N_{k}=0 \\ \end{aligned}
Interval II \(x\in (2,5) \)
\begin{array}{ll} Q_{k}=V_{A}=-1-0.2 x & \\ Q_{k}(2)=0.6 & Q_{k}(5)=0 \end{array} \begin{aligned} &M_{k}=V_{A} \cdot 2=2-0.4 x \\ &M_{k}(2)=1.2 \quad M_{k}(5)=0 \end{aligned} \begin{aligned} N_k=0 \end{aligned}Graphics

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